QFL Uno Free Agency Starts Tonight

The first round of pre-season free agency starts tonight in QFL1. Send all bids to the commishq yahoo email address. NO TREE BIDS. If you include even ONE tree bid your email will be ignored. As usual ties will be broken by the sketchy random number system Ted came up with a few years ago.

From Commish Shane.

Here is this year’s schedule for free agency and waivers during the NFL preseason:

Tuesday, Aug. 23: No Waivers yet.

Wednesday, August 24: Free agency bids due at 11:59P.M. to commissionerq@yahoo.com

Tuesday, August 30: Waiver claims due at 11:59P.M. to commissionerq@yahoo.com

Wednesday, August 31: Free agency bids due at 11:59P.M. to commissionerq@yahoo.com

Tuesday, September 6: Waiver claims due at 11:59P.M. to commissionerq@yahoo.com

Wednesday, September 7: Free agency bids due at 11:59P.M. to commissionerq@yahoo.com

September 8: Thursday Night Football (make sure rosters are compliant if TNF players are in your lineup)

Tuesday, September 13: Submit waiver claims through ASS

Wednesday, September 14: Submit free agency claims through ASS

And as a reminder, here is what Paul emailed out last year as to how the free agent tiebreaker system works:

1) A random list of 30 numbers from 1-12 will be generated from the
website http://www.random.org/integers/ and sent out to the league
sometime on Wednesday.
2) Each team’s number will correspond to its team number on A.S.S.
3) Ties will be broken in alphabetical order according to the player
in question (last name then first), and each specific tie is broken
before we move to the next tie. The closest team number in a given
tie wins, or we move to the next number. To be fair, numbers 1 and 12
will be considered 1 number away, ie if the number is 12, and teams 1
and 11 are involved, this is a tie. The same would be the case if the
number is 12 and teams 2 and 10 are involved. This should prevent any
given team number from having any advantage. Here is an example:

This is a sample number list of 10 random numbers:
12
10
4
7
4
8
1
12
5
6

Say there are 3 ties:
Scott (team 10) and Ted (team 5) both bid $2 on John Doe
Rishi (team 3) and Paul (team 4) both bid $3 on John Smith
Shane (team 12) , Jay (team 2) and Seth (team 6) all bid $4 Joe Doe

The order of determination would be:
Joe Doe, John Doe, John Smith

Tie #1:
The number is 12, so Scott would win this tie (10 closer to 12 than 5).

Tie #2
We move to the second number which is 10. Rishi (3) is actually
closer to 10 than Paul (4) going in reverse so he wins.

Tie #3
We go to the third number which is 4. Jay (2) and Seth (6) tie again
but Shane (12) is eliminated.
We go to the 4th number, 7. Seth wins the tie

Tie #4 would start with the 5th number.